10=-x^2+2/8

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Solution for 10=-x^2+2/8 equation: 



10=-x^2+2/8

We move all terms to the left:

10-(-x^2+2/8)=0

We get rid of parentheses

x^2+10-2/8=0

We multiply all the terms by the denominator


x^2*8-2+10*8=0

We add all the numbers together, and all the variables

x^2*8+78=0

Wy multiply elements

8x^2+78=0

a = 8; b = 0; c = +78;
Δ = b2-4ac
Δ = 02-4·8·78
Δ = -2496
Delta is less than zero, so there is no solution for the equation

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